(3x/x^2+2x)-(1/2x)

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Solution for (3x/x^2+2x)-(1/2x) equation:


D( x )

x^2 = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

2*x-((1/2)*x)+(3*x)/(x^2) = 0

2*x+(-1/2)*x+(3*x)/(x^2) = 0

3/2*x^1+3*x^-1 = 0

(3/2*x^2+3*x^0)/(x^1) = 0 // * x^2

x^1*(3/2*x^2+3*x^0) = 0

x^1

(3/2)*x^2+3 = 0

(3/2)*x^2+3 = 0

DELTA = 0^2-(3*4*(3/2))

DELTA = -18

DELTA < 0

x in { }

x belongs to the empty set

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